Faraday's Law: EMF from a Changing Area
1 · Predict
A loop of wire sits in a fixed magnetic field, but the loop's own area oscillates (imagine it stretching and shrinking). Does this also induce an EMF, the same way a changing field strength does?
- Yes — Faraday's law only cares about the total flux Φ = BA changing, regardless of whether B or A is what's varying.
- No — only a changing field strength induces EMF, not a changing area.
- A changing area induces EMF, but through a completely different mechanism than a changing field.
2 · Set Up
- Open the changing-flux-area preset and press Reset. The field is fixed at 0.5 T; the loop's area oscillates as A(t) = 0.025 m² × (1 + 0.35 cos(2π × 0.35Hz × t)).
- Enable the induced-EMF readout.
- Read the induced EMF at each listed time.
3 · Collect Data
| Time t (s) | Induced EMF (mV) |
|---|---|
| 0.5 | |
| 1 | |
| 1.5 |
Plot induced EMF (y-axis) against time t (x-axis) for your three readings, and sketch how it oscillates over one full period (≈2.86 s).
4 · Analyze
- For one trial, compute EMF = −B·dA/dt = B₀·A₀·0.35·ω·sin(ωt) using B₀ = 0.5 T, A₀ = 0.025 m², ω = 2π×0.35 rad/s. Compare to the table.
- Compare this formula's structure to the changing-flux-b experiment's. Explain why both give an EMF proportional to the product of the FIXED quantity (B here, A there) and the rate of change of the VARYING quantity.
5 · Extend
- A classic 'sliding rod' generator changes a circuit's enclosed area by physically moving one side, inducing EMF = BLv (field × rod length × sliding speed) — a mechanical version of exactly this changing-area effect. Explain why sliding the rod faster increases the induced EMF.
- Some microphones work by having a magnet vibrate near (or a coil's effective area change relative to) a fixed field, converting sound vibrations into a changing flux and therefore a voltage signal. Why does a louder sound (bigger vibration amplitude) produce a bigger EMF signal?
The Physics Behind This Experiment
Faraday's Law (Changing Area)
Magnetic flux through a loop is Φ = BA. When A changes in time (B fixed), Faraday's law still applies: EMF = −dΦ/dt = −B·dA/dt — the same law, just with the roles of B and A swapped.