Converging Lens: Real Images Beyond 2f
1 · Predict
An object sits beyond a converging lens's focal length. As you move it farther from the lens, does the real image formed on the other side move closer to the lens or farther away?
- Closer to the lens — a farther object forms its image nearer the focal point.
- Farther from the lens.
- The image distance doesn't depend on object distance.
2 · Set Up
- Open the converging-real preset and press Reset. The lens's focal length is fixed at 10 cm.
- Enable the image-distance and magnification readouts.
- Set the object distance for each trial and record the image distance and magnification.
3 · Collect Data
| Object distance d_o (cm) | Image distance d_i (cm) | Magnification m |
|---|---|---|
| 15 | ||
| 20 | ||
| 30 |
Plot 1/d_i (y-axis) against 1/d_o (x-axis) for your three trials. Is the line straight?
4 · Analyze
- For one trial, compute d_i from 1/f = 1/d_o + 1/d_i using f = 10 cm, then m = −d_i/d_o. Compare both to the table.
- Explain, using the thin-lens equation, why moving the object farther from the lens (increasing d_o) makes the image distance shrink toward the focal length.
5 · Extend
- Every trial gives a negative magnification. Explain what a negative m means physically for the orientation of the image compared to the object.
- A camera lens forms a real image on the sensor for any object beyond the focal length. Explain, using your data, why photographing something very far away (d_o ≫ f) always places the image very close to the focal plane.
The Physics Behind This Experiment
Thin-Lens Equation
For a thin lens, object distance, image distance, and focal length are related by 1/f = 1/d_o + 1/d_i. This single equation covers converging and diverging lenses alike, using signed distances.
Lateral Magnification
The image's size relative to the object is m = −d_i/d_o. A negative m means an inverted image; |m| > 1 means the image is enlarged.