Converging Lens: Real Images Beyond 2f

1 · Predict

An object sits beyond a converging lens's focal length. As you move it farther from the lens, does the real image formed on the other side move closer to the lens or farther away?

2 · Set Up

  1. Open the converging-real preset and press Reset. The lens's focal length is fixed at 10 cm.
  2. Enable the image-distance and magnification readouts.
  3. Set the object distance for each trial and record the image distance and magnification.

3 · Collect Data

Object distance d_o (cm)Image distance d_i (cm)Magnification m
15
20
30

Plot 1/d_i (y-axis) against 1/d_o (x-axis) for your three trials. Is the line straight?

4 · Analyze

  1. For one trial, compute d_i from 1/f = 1/d_o + 1/d_i using f = 10 cm, then m = −d_i/d_o. Compare both to the table.
  2. Explain, using the thin-lens equation, why moving the object farther from the lens (increasing d_o) makes the image distance shrink toward the focal length.

5 · Extend

  1. Every trial gives a negative magnification. Explain what a negative m means physically for the orientation of the image compared to the object.
  2. A camera lens forms a real image on the sensor for any object beyond the focal length. Explain, using your data, why photographing something very far away (d_o ≫ f) always places the image very close to the focal plane.

The Physics Behind This Experiment

Thin-Lens Equation

For a thin lens, object distance, image distance, and focal length are related by 1/f = 1/d_o + 1/d_i. This single equation covers converging and diverging lenses alike, using signed distances.

Lateral Magnification

The image's size relative to the object is m = −d_i/d_o. A negative m means an inverted image; |m| > 1 means the image is enlarged.

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