Doppler Effect: A Source Approaching a Listener
1 · Predict
A sound source moves toward a stationary listener while emitting a steady tone. Does the listener hear a higher, lower, or the same pitch as the source's true frequency?
- The listener hears a higher pitch than the source's true frequency.
- The listener hears the exact same pitch.
- The listener hears a lower pitch.
2 · Set Up
- Open the doppler-approach preset and press Reset. The source emits 440 Hz in 20°C air; the listener is stationary.
- Enable the observed-frequency readout at the observer.
- Set the source's approach speed for each trial and record the observed frequency.
3 · Collect Data
| Source frequency f (Hz) | Source speed v_s (m/s) | Observed frequency f′ (Hz) |
|---|---|---|
| 440 | 20 | |
| 440 | 35 | |
| 440 | 50 |
Plot observed frequency f′ (y-axis) against source speed v_s (x-axis) for your three trials.
4 · Analyze
- For one trial, compute f′ = f·c/(c − v_s) using c = 331.3·√(1 + 20/273.15) m/s for 20°C air. Compare to the table.
- Explain why f′ keeps increasing as v_s grows, and what would happen to the formula (and to the sound) if v_s ever reached the speed of sound c.
5 · Extend
- An ambulance siren sounds higher-pitched as it approaches and suddenly drops in pitch as it passes and recedes. Use the Doppler formula's sign convention to explain the drop.
- This experiment only covers an approaching source. If the source were moving away instead, would you expect (c − v_s) to become (c + v_s) in the denominator? Explain what that does to f′.
The Physics Behind This Experiment
Doppler Effect (moving source)
A source moving toward a stationary listener compresses the wavefronts ahead of it, raising the frequency the listener hears: f′ = f·c/(c − v_s).