Thermal Conduction: Heat Flow Through a Bar

1 · Predict

A copper bar connects a hot body and a cold body. If you use a thicker bar (more cross-sectional area), does heat flow through it faster or slower?

2 · Set Up

  1. Open the conduction-bar preset and press Reset. A copper bar (k = 401 W/(m·K), length 0.1 m) connects a 450 K body to a 300 K body.
  2. Enable the heat-flow-rate readout on the conductor.
  3. Set the bar's cross-sectional area for each trial and record the heat-flow rate.

3 · Collect Data

Cross-sectional area A (m²)Heat-flow rate Q̇ (W)
0.0005
0.001
0.002

Plot heat-flow rate Q̇ (y-axis) against cross-sectional area A (x-axis) for your three trials. Is the line straight through the origin?

4 · Analyze

  1. For one trial, compute Q̇ = kAΔT/L using k = 401 W/(m·K), ΔT = 150 K, L = 0.1 m. Compare to the table.
  2. Explain, using Fourier's law, why doubling the bar's cross-sectional area doubles the rate of heat flow at fixed temperature difference and length.

5 · Extend

  1. A material with low thermal conductivity (like glass, k ≈ 0.8 W/(m·K)) conducts heat far more slowly than copper (k = 401 W/(m·K)) for the same area and length. Explain why house insulation uses low-k materials.
  2. This experiment varies area, but the formula also has length L in the denominator. Would doubling the bar's length double or halve the heat-flow rate? Explain why a longer path resists heat flow more.

The Physics Behind This Experiment

Fourier's Law of Conduction

Heat flows through a material at a rate set by its conductivity, cross-sectional area, temperature difference, and length: Q̇ = kAΔT/L. Bigger area or temperature difference speeds up conduction; a longer path slows it down.

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