Calorimetry: Mixing Hot and Cold
1 · Predict
A hot aluminium block is dropped into cooler water. If you use a bigger aluminium block (more mass) at the same starting temperature, does the final equilibrium temperature go up or down?
- A bigger hot block raises the final equilibrium temperature.
- A bigger hot block lowers the final equilibrium temperature.
- The final temperature doesn't depend on the aluminium block's mass.
2 · Set Up
- Open the hot-cold-mix preset and press Reset. 1 kg of water at 290 K (body1) will mix with an aluminium block at 400 K (body2).
- Enable the equilibrium-temperature readout.
- Set the aluminium block's mass for each trial and record the equilibrium temperature.
3 · Collect Data
| Aluminium mass m₂ (kg) | Equilibrium temperature T_eq (K) |
|---|---|
| 0.3 | |
| 0.5 | |
| 0.8 |
Plot equilibrium temperature T_eq (y-axis) against aluminium mass m₂ (x-axis) for your three trials.
4 · Analyze
- For one trial, compute T_eq = (m₁c₁T₁ + m₂c₂T₂) / (m₁c₁ + m₂c₂) using water m₁ = 1 kg, c₁ = 4186 J/(kg·K), T₁ = 290 K, and aluminium c₂ = 900 J/(kg·K), T₂ = 400 K. Compare to the table.
- Explain why increasing the hot block's mass pulls the equilibrium temperature higher, even though its specific heat (900 J/(kg·K)) is much lower than water's (4186 J/(kg·K)).
5 · Extend
- Water has an unusually high specific heat compared to most materials. Explain why coastal climates tend to have milder temperature swings than inland areas, using the same energy-balance idea as this experiment.
- The heat lost by the aluminium block should exactly equal the heat gained by the water (energy conservation, assuming no losses to the surroundings). For one trial, verify this using Q = mcΔT for each body.
The Physics Behind This Experiment
Calorimetric Equilibrium Temperature
When two bodies exchange heat with no losses to the surroundings, they settle at a weighted-average temperature — weighted by each body's heat capacity m·c, not just its mass.