De Broglie Matter Waves: An Electron's Wavelength

1 · Predict

Louis de Broglie proposed that particles like electrons have a wavelength too, not just light. Does a faster (higher kinetic energy) electron have a longer or shorter de Broglie wavelength?

2 · Set Up

  1. Open the electron-de-broglie preset and press Reset.
  2. Enable the de Broglie wavelength readout.
  3. Set the electron's kinetic energy for each trial and record its de Broglie wavelength.

3 · Collect Data

Kinetic energy K (eV)De Broglie wavelength λ (pm)
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Plot wavelength λ (y-axis) against 1/√K (x-axis) for your three trials. Is the line straight through the origin?

4 · Analyze

  1. For one trial, compute λ = h/√(2m_eK) using h = 6.626×10⁻³⁴ J·s, m_e = 9.109×10⁻³¹ kg (converting K from eV to joules). Compare to the table.
  2. Explain, using λ = h/p and p = √(2m_eK), why higher kinetic energy (and therefore higher momentum) produces a SHORTER wavelength — the opposite relationship from a photon's E = hc/λ.

5 · Extend

  1. Electron microscopes exploit an electron's tiny de Broglie wavelength (much shorter than visible light) to resolve details far smaller than an optical microscope ever could. Explain why using higher-energy electrons (shorter wavelength) generally improves an electron microscope's resolution.
  2. A thrown baseball also has a de Broglie wavelength, but far too small to ever notice. Using λ = h/p with a baseball's typical momentum, explain why matter-wave effects are only observable for extremely light particles like electrons.

The Physics Behind This Experiment

De Broglie Wavelength

Every particle with momentum p has an associated wavelength λ = h/p. For a non-relativistic particle with kinetic energy K, this becomes λ = h/√(2mK) — a direct extension of light's wave-particle duality to matter.

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