The Photoelectric Effect: A Sharp Energy Threshold

1 · Predict

Light of different wavelengths hits a metal with work function 2.3 eV. As long as both wavelengths are above the threshold, does a bluer (shorter-wavelength) photon eject an electron with more kinetic energy?

2 · Set Up

  1. Open the photoelectric-threshold preset and press Reset. The photocell's work function is fixed at 2.3 eV.
  2. Enable the photon-energy and maximum-kinetic-energy readouts.
  3. Set the light's wavelength for each trial and record the maximum kinetic energy of ejected electrons.

3 · Collect Data

Wavelength λ (nm)Photon energy E_γ (eV)Max kinetic energy K_max (eV)
300
350
400

Plot K_max (y-axis) against 1/λ (x-axis) for your three trials. Is the line straight?

4 · Analyze

  1. For one trial, compute E_γ = hc/λ using h = 6.626×10⁻³⁴ J·s, c = 3×10⁸ m/s, then K_max = E_γ − φ using φ = 2.3 eV. Compare both to the table.
  2. Explain why K_max increases linearly with photon energy (and therefore with 1/λ) once you're above threshold, with a slope of exactly 1 and a y-intercept of −φ.

5 · Extend

  1. Classical wave theory predicted that even dim, low-frequency light should eventually eject electrons if you wait long enough or turn up the intensity. Explain why the photoelectric effect's sharp energy threshold (independent of intensity) was so surprising before Einstein's photon explanation.
  2. If you doubled the light's intensity at the same wavelength, would K_max change? What would change instead?

The Physics Behind This Experiment

Photon Energy

A photon's energy depends only on its wavelength (or frequency): E = hc/λ = hf. Shorter wavelength means higher-energy photons.

Maximum Photoelectron Kinetic Energy

Einstein's photoelectric equation: an incoming photon's energy first pays the work function (the energy binding an electron to the metal), and whatever's left over becomes the ejected electron's kinetic energy: K_max = E_γ − φ.

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