Relativistic Electrons: When Classical Momentum Fails
1 · Predict
A 400 keV electron moves fast enough that relativistic effects matter (β ≈ 0.83). Does using the simple non-relativistic de Broglie formula λ = h/√(2mK) still give an accurate wavelength at this energy?
- Yes — the non-relativistic formula still works fine at any electron energy.
- No — at this energy the electron's momentum must be computed relativistically; the non-relativistic formula would be noticeably wrong.
- Wavelength calculations don't depend on relativistic effects at all.
2 · Set Up
- Open the electron-ke-comparison preset and press Reset. This preset's default kinetic energy is 400 keV, giving β ≈ 0.83.
- Enable the de Broglie wavelength readout.
- Set the electron's kinetic energy for each trial (all in the relativistic regime) and record its de Broglie wavelength using the relativistic momentum formula.
3 · Collect Data
| Kinetic energy K (eV) | De Broglie wavelength λ (pm) |
|---|---|
| 200000.00 | |
| 400000.00 | |
| 600000.00 |
Plot wavelength λ (y-axis) against kinetic energy K (x-axis) for your three trials.
4 · Analyze
- For one trial, compute the relativistic momentum via pc = √(K(K + 2m_ec²)) (with m_ec² ≈ 511 keV, the electron's rest energy), then λ = hc/(pc) — converting units carefully. Compare to the table.
- Explain why the relativistic momentum formula pc = √(K(K + 2mc²)) reduces to the familiar non-relativistic p = √(2mK) when K is much smaller than the rest energy mc² — and why that approximation breaks down once K becomes comparable to or larger than mc².
5 · Extend
- An electron's rest energy m_ec² ≈ 511 keV. At 400 keV kinetic energy, the electron's total energy is already about 78% more than its rest energy — solidly in the relativistic regime. Explain why physicists have a rule of thumb that relativistic corrections become important once kinetic energy approaches roughly 10% of rest energy.
- Particle accelerators routinely reach kinetic energies enormously larger than a particle's rest energy (ultra-relativistic). Explain why, in that extreme limit, pc ≈ K (momentum-energy and kinetic energy become nearly equal) even though that's clearly not true at everyday, non-relativistic speeds.
The Physics Behind This Experiment
Relativistic Kinetic Energy
A relativistic particle's kinetic energy is K = (γ − 1) m₀c², where γ = 1/√(1 − v²/c²) — the total relativistic energy γm₀c² minus its rest energy m₀c². Unlike the non-relativistic K = ½mv², this stays finite and correct as v approaches c, diverging sharply from the classical formula at high speed.
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